x^3+x^2-4x+3=x(x^2-1)+21

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Solution for x^3+x^2-4x+3=x(x^2-1)+21 equation:


Simplifying
x3 + x2 + -4x + 3 = x(x2 + -1) + 21

Reorder the terms:
3 + -4x + x2 + x3 = x(x2 + -1) + 21

Reorder the terms:
3 + -4x + x2 + x3 = x(-1 + x2) + 21
3 + -4x + x2 + x3 = (-1 * x + x2 * x) + 21
3 + -4x + x2 + x3 = (-1x + x3) + 21

Reorder the terms:
3 + -4x + x2 + x3 = 21 + -1x + x3

Add '-1x3' to each side of the equation.
3 + -4x + x2 + x3 + -1x3 = 21 + -1x + x3 + -1x3

Combine like terms: x3 + -1x3 = 0
3 + -4x + x2 + 0 = 21 + -1x + x3 + -1x3
3 + -4x + x2 = 21 + -1x + x3 + -1x3

Combine like terms: x3 + -1x3 = 0
3 + -4x + x2 = 21 + -1x + 0
3 + -4x + x2 = 21 + -1x

Solving
3 + -4x + x2 = 21 + -1x

Solving for variable 'x'.

Reorder the terms:
3 + -21 + -4x + x + x2 = 21 + -1x + -21 + x

Combine like terms: 3 + -21 = -18
-18 + -4x + x + x2 = 21 + -1x + -21 + x

Combine like terms: -4x + x = -3x
-18 + -3x + x2 = 21 + -1x + -21 + x

Reorder the terms:
-18 + -3x + x2 = 21 + -21 + -1x + x

Combine like terms: 21 + -21 = 0
-18 + -3x + x2 = 0 + -1x + x
-18 + -3x + x2 = -1x + x

Combine like terms: -1x + x = 0
-18 + -3x + x2 = 0

Factor a trinomial.
(-3 + -1x)(6 + -1x) = 0

Subproblem 1

Set the factor '(-3 + -1x)' equal to zero and attempt to solve: Simplifying -3 + -1x = 0 Solving -3 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '3' to each side of the equation. -3 + 3 + -1x = 0 + 3 Combine like terms: -3 + 3 = 0 0 + -1x = 0 + 3 -1x = 0 + 3 Combine like terms: 0 + 3 = 3 -1x = 3 Divide each side by '-1'. x = -3 Simplifying x = -3

Subproblem 2

Set the factor '(6 + -1x)' equal to zero and attempt to solve: Simplifying 6 + -1x = 0 Solving 6 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-6' to each side of the equation. 6 + -6 + -1x = 0 + -6 Combine like terms: 6 + -6 = 0 0 + -1x = 0 + -6 -1x = 0 + -6 Combine like terms: 0 + -6 = -6 -1x = -6 Divide each side by '-1'. x = 6 Simplifying x = 6

Solution

x = {-3, 6}

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